![]() The above equation is used to determine the magnitude of the magnetic field in a long solenoid.Īlso Read: Moving Charges and Magnetism MCQĮxample 1: Find out the magnetic field produced by the solenoid of length 80 cm under the number of turns of the coil is 360 and the current passing through is 15 A. “The integration of a magnetic field around a loop is directly proportional to the current enclosed in the loop.” ![]() Since the field outside the solenoid is comparatively less than that it is present inside, we can consider it as zero as the length of the solenoid increases, and hence B = 0.Īlso Read: Parallel Current Carrying Conductor The magnetic field outside a solenoid is: For the entire number of field lines to be contained, the magnetic field outside must be zero, because the solenoid gets longer.As a result of which, the field outside the solenoid is constant.Therefore, the density of the magnetic field lines outside the solenoid is decreased greatly.The longitudinal path of magnetic field lines is due to the formation of the loop from the lines. ![]()
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |